text{Phthalic anhydride} xrightarrow {PCl_5} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. Phthalic anhydride reacts with $PCl_5$ to form phthaloyl chloride $(A)$.$2$. Phthaloyl chloride is reduced by $LiAlH_4$ to form benzene$-1,2-

Vedclass · Accepted Answer

Vedclass · Answer

(A) $1$. Phthalic anhydride reacts with $PCl_5$ to form phthaloyl chloride $(A)$.$2$. Phthaloyl chloride is reduced by $LiAlH_4$ to form benzene$-1,2-$dimethanol $(B)$.$3$. Benzene$-1,2-$dimethanol is oxidized by $PCC$ to form phthalaldehyde $(C)$.$4$. Phthalaldehyde undergoes an intramolecular Cannizzaro reaction in the presence of $OH^-$ and $\Delta$ to form the phthalide anion,which is the salt of $2-$(hydroxymethyl)benzoic acid $(D)$.

$\text{Phthalic anhydride}$ $\xrightarrow {PCl_5} A$ $\xrightarrow {LiAlH_4} B$ $\xrightarrow {PCC} C$ $\xrightarrow [\Delta ] {OH^{-}} D$
Compound $D$ is :-

Similar Questions

In the given compound,how many functional groups are reduced by $LiAlH_4$ (Lithium aluminium hydride) and $NaBH_4$ (Sodium borohydride) respectively? (Assume the compound contains an ester,an acid,a ketone,and an aldehyde group).

The most appropriate reagent to distinguish between acetaldehyde and formaldehyde is

$A$ $(C_3H_6O)$ $\xrightarrow{NaCN/H_2SO_4}$ cyanohydrin of $A$. If the cyanohydrin is optically active,then the possible structure of $A$ is:

$CH_3-CH(OH)-CH_3 \xrightarrow{Cu/300^\circ C} \text{Product (X)}$. Which of the following is correct about product $X$?

Which of the following carbonyl compounds does $NOT$ undergo aldol condensation?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$\text{Phthalic anhydride}$ $\xrightarrow {PCl_5} A$ $\xrightarrow {LiAlH_4} B$ $\xrightarrow {PCC} C$ $\xrightarrow [\Delta ] {OH^{-}} D$ Compound $D$ is :-